1/4(9-q)^2=1/4(1+3q)

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Solution for 1/4(9-q)^2=1/4(1+3q) equation: 



1/4(9-q)^2=1/4(1+3q)

We move all terms to the left:

1/4(9-q)^2-(1/4(1+3q))=0



Domain of the equation: 4(9-q)^2!=0

q∈R





Domain of the equation: 4(1+3q))!=0

q∈R



We add all the numbers together, and all the variables

1/4(-1q+9)^2-(1/4(3q+1))=0

We calculate fractions


(4q3/(4(-1q+9)^2*4(3q+1)))+(-(1*4(-1q+9)^2)/(4(-1q+9)^2*4(3q+1)))=0



We calculate terms in parentheses: +(4q3/(4(-1q+9)^2*4(3q+1))), so:

4q3/(4(-1q+9)^2*4(3q+1))

We multiply all the terms by the denominator


4q3

We add all the numbers together, and all the variables

4q^3

We do not support eqpression: q^3

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